declaring jQuery objects with the $foo pattern

[Michelle D'Souza]

I've been using the assumption that everything is a jQuery unless  
specified. So:

var foo = $("div");

var fooEl = foo[0];

Michelle

On 21-Aug-08, at 2:40 PM, Eli Cochran wrote:

> Hi,
> There is a little discussion on the jQuery Google Group about using  
> $ when declaring variables that contain a jQuery object.
>
> So:
>
> 	var $foo = $("div");
>
> instead of just:
>
> 	var foo = $("div");
>
> Any opinions.
>
> I have a case, in the scroller, were I have to refer to an element  
> both as a jQuery object and a DOM object (because jQuery doesn't  
> support the method that I need) and it would make the code perhaps  
> clearer... at least to those who know the convention. Perhaps more  
> confusing to those who don't.
>
> - Eli
>
> . . . . . . . . . . .  .  .   .    .      .         .              .                     .
>
> Eli Cochran
> user interaction developer
> ETS, UC Berkeley
>
>
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------------------------------------------------------
Michelle D'Souza
Software Developer, Fluid Project
Adaptive Technology Resource Centre
University of Toronto



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